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Top Forums UNIX for Dummies Questions & Answers Need help to escape special characters in Korn shell script Post 302191337 by Thinkpositiv on Friday 2nd of May 2008 08:23:31 AM
Old 05-02-2008
Well, I got it myself. I missed the double quotes when using the variable (not a declaration time of the variable)!

Code:
#!/bin/ksh
typeset pattern="[a-zA-Z ]{30}:"
echo "Command to be executed: grep -E $pattern myFile"
grep -E "$pattern" myFile

Hope this helps someone Smilie
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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