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Top Forums Shell Programming and Scripting shell script with If then else Post 302174625 by skatpally on Tuesday 11th of March 2008 04:15:05 PM
Old 03-11-2008
shell script with If then else

Hii frds,
I am trying to write a shell script to display the date based on user input. I am geting syntax error. plz help. thanks - sam

UNIX version: AIX

#!/bin/ksh
echo -n "todays date want to know:"
set answer = $<
if ($answer == yes) then
date
exit 1
else
exit 2
endif


-n todays date want to know:
date1[3]: 0403-057 Syntax error at line 4 : `newline or ;' is not expected.
 

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DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)
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