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#1
02-22-2008
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du -sh Command
Hi all i am trying to list contents of a directory in summarised user readable form from file size highest to lowest?
I have used du -k * | sort -rn however this provides the output in KB if i use du -sh * this lists the contents but does not list in appropriate order e.g. some of the files in MB are listed below KB ones etc. I'm really struggling with this one and wondered if there are any experts who could help? I'm not bothered if they are listed ascending or descending as long as GB are above MB and MB are above KB Thanks, pure_jax 
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#3
02-22-2008
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As a starting, adjust to your needs. This can done more efficient, but it's done like this so you can see the concept.
Code:
du -sk * | sort -rn | \
while read SIZE ENTRY
do
# if size > 1048576 then it is at least 1 GB big
if [ ${SIZE} -gt 1048576 ]
then
NEWSIZE=`echo "${SIZE}000 / 1048576" | bc | sed -e "s/\(...\)$/\.\1/"`
printf "% 10s %s\n" ${NEWSIZE}G $ENTRY
# if size > 1024 then it is at least 1 MB big
elif [ ${SIZE} -gt 1024 ]
then
NEWSIZE=`echo "${SIZE}000 / 1024" | bc | sed -e "s/\(...\)$/\.\1/"`
printf "% 10s %s\n" ${NEWSIZE}M $ENTRY
else
printf "% 10s %s\n" ${SIZE}K $ENTRY
fi
done
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