display result from user input - Shell Programming and Scripting

thms_sum · #1 01-30-2008

how can i only display the result according to user input?

For example:
i have a data file(in the attachement), when the user enter "1" it will only display whole records with pid from the data file matches to the users entered.

Karthikeyan_113 · #2 01-31-2008

Try the below code.

Code:

echo "Enter the PID :"
read pid
linenum=`cat tes.txt | tr -s " " "|" | cut -d"|" -f2 |grep -n $pid`
cat tes.txt | head -$linenum | tail -1

Its giving the expected results.

==========
Thanks,
Karthikeyan.
==========

thms_sum · #3 01-31-2008

hi Karthikeyan_113! i have error when i run the code.

error shown:
head: unrecongonized option `-:'

KevinADC · #4 01-31-2008

Does it have to be awk/ksh? Can you use perl?

ghostdog74 · #5 01-31-2008

Code:

awk 'BEGIN{
 printf "%s : " ,"What Pid"
 getline pid <"-" 
}
$1==pid'  "file"

ghostdog74 · #6 01-31-2008

Quote:

Originally Posted by KevinADC

Does it have to be awk/ksh? Can you use perl?

you could just post your Perl solution. If OP wants a Perl solution, he will use it.

KevinADC · #7 01-31-2008

Edit: Do not try this code, it's got a couple of errors. See below for corrected version.

Quote:

Originally Posted by ghostdog74

you could just post your Perl solution. If OP wants a Perl solution, he will use it.

You're right mate. I am not sure what he wants printed out, the whole line or just part of the data, but this prints the whole line associated with the PID number:

Code:

use strict;
use warnings;
print "Enter the PID :"
my $pid = <STDIN>;
chomp $pid;
open (IN , "tes.txt");
while (<IN>) {
   print if (/^\s*$pid\s/); 
   last;
}
close IN;
exit;

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