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Thread: passing a variable inside a variable to a function
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Old 01-14-2008
gus2000 gus2000 is offline
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Join Date: Oct 2007
Posts: 155
Ah, you want the shell to parse "$C$x" as "$C1" but instead it is doing "$C" + "$x". So, you need to force it to evaluate $x first.

Code:
# C1=abc
# x=1 
# echo $C$x
1
# eval echo \$C$x
abc
Is that what you were looking for?
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