Hello, my name is Marc, I'm a linux starter and I hope you specialists can help me solving this issue.

I have a file containing a lot of data. Somewhere in this file, there's a string called "Faultdump", directly followed by 64 chars of HEX data. I need to get the HEX part. I accomplished this with several lines of code in a script calling sed, cut as well as head/tail. I know some of you guys will manage to get this on one line by using just awk or sed by avoiding cat or head/tail. Please can anyone of you point me to the right direction?

I was searching through the forums, but I'm afraid, I couldn't find an appropriate example.

Many thanks in advance!

Marc (Kally).

sed -n 's/.*Faultdump\(.*\)/\1/p' filename| cut -c1-64

Should work.

Sure someone will improve on that though.

HTH

Thanks Tytalus, I'll try it later. Looks a lot better than my commandlines.

If someone else has got another approach (using sed or awk completely alone), I'll appreciate that.

Anyway, I'm fine with Tytalus' solution, though.

Many thanks.

I'm afraid, I tried it and it doesn't work properly, does anyone got another approach, may using AWK? I'm stuck.

Thank you very much.

awk '{ if(substr($0,65,9)=="Faultdump") print substr($0,1,64)}' filename

@ranjithpr:

Thank you! I'll give you a report later then. Desi Greetings.

Marc.

think that that awk will only work if the string faultdump starts at char 65.

so...

you could try :

grep Faultump <filename> | sed 's/.*Faultdump//' | cut -c1-64

What errors are you seeing when you try the earlier sed I gave ?