12-14-2007
grep string and find line before
hi,
i have to grep for string in file but i want to find the group of this line so i must get lines before and select the group.
the file look like :
####name_groupe1
alphanumeric line
alphanumeric line
..
####name_groupe2
alphanumeric line
alphanumeric line
..
####name_groupe3
alphanumeric line
alphanumeric line
..
al the file is like that :
i want to grep string if i find it in line i want to gret the name_group
i use :
grep -n "string to search" file | cut -f1 -d: to get the line number but i want to go lines before to find the group and store that in variable.
i use script shell.
thanks
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GREP(1) General Commands Manual GREP(1)
NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS
-e -e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)