Sponsored Content
Top Forums UNIX for Dummies Questions & Answers how to get first two characters from a word Post 302149563 by broli on Thursday 6th of December 2007 02:32:47 PM
Old 12-06-2007
you can use cut
echo $somevar | cut -c 2
i dont know if its the best option, but is the most straight forward
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Word Count without any characters but the Output String

Hi all, I am logging any access to a server, and i wanted to write a script which tells me how much entries there are. The Problem is that "wc -l log" outputs the correct number of lines but with the name of the file attached. is there any nice possibility to solve this that i ONLY... (3 Replies)
Discussion started by: JP_II
3 Replies

2. Shell Programming and Scripting

Print the characters in a word

Hi, How can I split the characters in a word? For Eg: If my input is: command my output should be: c o m m a n d Please help me in doing it so. (5 Replies)
Discussion started by: chella
5 Replies

3. Shell Programming and Scripting

deleting last characters of a word

Hi All is there a way to delete last n characters from a word like say i have employee_new i want to delete _new. and just get only employee I want this in AIX Shell scripting Thanks (3 Replies)
Discussion started by: rajaryan4545
3 Replies

4. Shell Programming and Scripting

Help to fetch first two characters from a word in perl

Hi All, I have a word "DE_PR_Package__Basic" , i need to check if the first two characters of this words is DE or something else using perl script. Can anyone pls let me know how to proceed? Thanks in advance. Giri! (3 Replies)
Discussion started by: girish.raos
3 Replies

5. Shell Programming and Scripting

Adding Characters to a Word List

If I had a word list with a large amount of words in it, how would I (using a unix command) add, say, 123 to the end of each word? EDIT: The word list is stored in a large text file. I need a command that applies the ending to each word in the file and saves the result in a new text file. (7 Replies)
Discussion started by: evillion
7 Replies

6. UNIX for Dummies Questions & Answers

find a word in a file, plus the next 6 characters?

I plan to use sed in a script to replace a string. My problem is the last 6 characters of the word to be replaced can be different each time, plus it's not always in the same spot on the line so I can't use cut or nawk to get the field. So I am looking for a way to find a certain word in a file,... (6 Replies)
Discussion started by: mikayla73
6 Replies

7. Shell Programming and Scripting

Find word in file then get following characters

Hello, I have several xml files from which I want to find and return a particular string I want to locate the InId="00000008". Now that is inlcuded within a tag and ofcourse the number is different every time this is what I came up with given that after greping the line that contains the... (6 Replies)
Discussion started by: TasosARISFC
6 Replies

8. Shell Programming and Scripting

Search for the word and exporting 35 characters after that word using shell script?

I have a file input.txt which have loads of weird characters, html tags and useful materials. I want to display 35 characters after the word description excluding weird characters like $$#$#@$#@***$# and without html tags in the new file output.txt. Help me. Thanx in advance. My final goal is to... (11 Replies)
Discussion started by: sachit adhikari
11 Replies

9. Shell Programming and Scripting

Search for the word and exporting 35 characters after that word using shell script

I have a file input.txt which have loads of weird characters, html tags and useful materials. I want to display 35 characters after the word "description" excluding weird characters like $&lmp and without html tags in the new file output.txt. Help me. Thanx in advance. I have attached the input... (4 Replies)
Discussion started by: sachit adhikari
4 Replies

10. Shell Programming and Scripting

Grep a word that contains minimum 5 or 6 same characters

Hi, I am looking for a solution to grep for minimum 5 or 6 characters in a file, otherwise ignore. Example 1121221222 2212121211 1221122122 2121222222 2222112222 1211221121 So it greps 5 X 1 or 6 X 1 2212121211 1211221121 Thanks for you help (6 Replies)
Discussion started by: stinkefisch
6 Replies
cut(1)								   User Commands							    cut(1)

NAME
cut - cut out selected fields of each line of a file SYNOPSIS
cut -b list [-n] [file...] cut -c list [file...] cut -f list [-d delim] [-s] [file...] DESCRIPTION
Use the cut utility to cut out columns from a table or fields from each line of a file; in data base parlance, it implements the projection of a relation. The fields as specified by list can be fixed length, that is, character positions as on a punched card (-c option) or the length can vary from line to line and be marked with a field delimiter character like <TAB> (-f option). cut can be used as a filter. Either the -b, -c, or -f option must be specified. Use grep(1) to make horizontal ``cuts'' (by context) through a file, or paste(1) to put files together column-wise (that is, horizontally). To reorder columns in a table, use cut and paste. OPTIONS
The following options are supported: list A comma-separated or blank-character-separated list of integer field numbers (in increasing order), with optional - to indicate ranges (for instance, 1,4,7; 1-3,8; -5,10 (short for 1-5,10); or 3- (short for third through last field)). -b list The list following -b specifies byte positions (for instance, -b1-72 would pass the first 72 bytes of each line). When -b and -n are used together, list is adjusted so that no multi-byte character is split. -c list The list following -c specifies character positions (for instance, -c1-72 would pass the first 72 characters of each line). -d delim The character following -d is the field delimiter (-f option only). Default is tab. Space or other characters with special meaning to the shell must be quoted. delim can be a multi-byte character. -f list The list following -f is a list of fields assumed to be separated in the file by a delimiter character (see -d ); for instance, -f1,7 copies the first and seventh field only. Lines with no field delimiters will be passed through intact (use- ful for table subheadings), unless -s is specified. -n Do not split characters. When -b list and -n are used together, list is adjusted so that no multi-byte character is split. -s Suppresses lines with no delimiter characters in case of -f option. Unless specified, lines with no delimiters will be passed through untouched. OPERANDS
The following operands are supported: file A path name of an input file. If no file operands are specified, or if a file operand is -, the standard input will be used. USAGE
See largefile(5) for the description of the behavior of cut when encountering files greater than or equal to 2 Gbyte (2**31 bytes). EXAMPLES
Example 1: Mapping user IDs A mapping of user IDs to names follows: example% cut -d: -f1,5 /etc/passwd Example 2: Setting current login name To set name to current login name: example$ name=`who am i | cut -f1 -d' '` ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables that affect the execution of cut: LANG, LC_ALL, LC_CTYPE, LC_MES- SAGES, and NLSPATH. EXIT STATUS
The following exit values are returned: 0 All input files were output successfully. >0 An error occurred. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ |CSI |Enabled | +-----------------------------+-----------------------------+ |Interface Stability |Standard | +-----------------------------+-----------------------------+ SEE ALSO
grep(1), paste(1), attributes(5), environ(5), largefile(5), standards(5) DIAGNOSTICS
cut: -n may only be used with -b cut: -d may only be used with -f cut: -s may only be used with -f cut: cannot open <file> Either file cannot be read or does not exist. If multiple files are present, processing continues. cut: no delimiter specified Missing delim on -d option. cut: invalid delimiter cut: no list specified Missing list on -b, -c, or -f option. cut: invalid range specifier cut: too many ranges specified cut: range must be increasing cut: invalid character in range cut: internal error processing input cut: invalid multibyte character cut: unable to allocate enough memory SunOS 5.10 29 Apr 1999 cut(1)
All times are GMT -4. The time now is 04:08 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy