And grep doesn't catch this string, even it exists there. I think it's a problem with passing $SPAMH to grep. I tried "$SPAMH", '$SPAMH', `$SPAMH` etc, but it doesn't help.
Please advice me how to make it working..
Thanks
I am trying to pass 2 shell variable's ("START" and "END") define earlier in the script to this awk statement, but i can't seem to pass it on. PLs help.
set START = xxxx
set END = yyyy
set selected_file = `awk '/$START/,/$END/' filename` (24 Replies)
Hi,
I have a master BASH shell script where I define a bunch of variables:
$var1=why
$var2=is
$var3=(this so hard)
I would then like to call another shell script and pass these variables to it:
$script2 $var1 $var2 $var3
This works fine for var1 and var2. However, var3 is an array,... (9 Replies)
Please help. I got these error. I'm try to pass variable extract from data-file.txt to sql file(select.sql).
cat: cannot open select
cat: cannot open *
cat: cannot open from
cat: cannot open user
cat: cannot open where
cat: cannot open name=$list;
#!/bin/bash
list=`sed q... (3 Replies)
Hello expert.
I have a little problem here.
I write a script and stuck some bug to fix.
I found the problem was about * and a sample of script is below.
line 1 is print * out
but line 3 print all name of files in the script's path. (but I want *)
I want to contain * in variable... (3 Replies)
Hi All,
I am using SFTP command to transfer the file.
SRC=`pwd`
DIG=123
/bin/sftp -B /dev/stdin xyz@abc.net <<::
mput ${SRC}/GGG.${DIG}.tar.gz
bye
::
The problem is, after entring into sftp command, it is not taking variable values of SRC and DIG.
can someone help me... (0 Replies)
Hello again :)
Am currently trying to write a function which will delete a record from a file.
The code currently looks as such:
function deleteRecord() {
clear
read -p "Please enter the ID of the record you wish to remove: " strID
... (2 Replies)
Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
This script file will be copied to /etc/init.d.
A string in this copy will be replaced with current directory value.
Below is original script file:
... (6 Replies)
Hi!
I was looking for files to clean out, and I remembered reading somewhere that you could pipe the output of grep to rm. But I prefer to mv stuff to ~/.Trash/
I thought I'd try something like this:
ls ~/Library/Preferences/ |grep '.*.\.iTunes\.plist\..*' |xargs -J % mv % ~/.Trash/
I... (12 Replies)
Hi All,
How to pass date variable to a query?
I have tried the below one , but it's not working.
ost.ksh
#!/bin/ksh
v_date=$1
var=$(sqlplus -s $ORACON <<ENDOFSQL
SELECT TO_DATE('$v_date','DD-MON-YYYY'),-1) FROM DUAL;
exit;
ENDOFSQL
)
#End
I have executed as below. (7 Replies)
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)
Discussion started by: ektubbe
8 Replies
LEARN ABOUT NETBSD
zegrep
ZGREP(1) BSD General Commands Manual ZGREP(1)NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD December 28, 2003 BSD