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Old 10-08-2007
netmaster netmaster is offline
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Join Date: Nov 2005
Posts: 6
Unix grep/test command

Hello, i have a script which checks if the user entered 8 numeric characters in the form of YYYYMMDD (birth date). If the user entered any non numeric characters, an error will be displayed:

Code:


# Check to see if the 8 characters are all numbers
# If not show error essage
# And prompt user for more input

         echo $char | grep -q '^[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]$'  
if 	[ $? -ne 0 ]
then
         echo "You have entered non-numeric values.  Please type in the form of YYYYMMDD"
	read char
        continue

Is there a simpler way to write this command without using the [0-9] value for each field? Any help would be appreciated