
06-20-2007
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Registered User
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Join Date: Mar 2006
Location: Bangalore,India
Posts: 1,397
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Quote:
Originally Posted by knowledge_gain
Using grep -o in linux, it gives the list wherever the pattern appears. The file
input_file has "Hello World
Hi Hello Hello Hello
Hello
Bye
"
for eg: grep -o "Hello" input_file
Hello
Hello
Hello
Hello
Hello
sed -n -e "s/.*\(Hello\).*/\1/p" input_file
But in using sed, it prints One Hello per line, becoz of \1.
Is it any other way to print same as in linux.
TIA
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Code:
sed -n -e "s/\(Hello\)/\1\\
/gp" file | sed -n -e "s/.*\(Hello\).*/\1/p"
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