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  #7 (permalink)  
Old 05-31-2007
ghostdog74 ghostdog74 is offline Forum Advisor  
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Join Date: Sep 2006
Posts: 2,554
this one doesn't use cal
Code:
count=0
month="05"
for s in `seq 1 31`
do
 fr=$(date +%a --date="2007-$month-$s" )
 if [ "$fr" == "Fri" ];then
     friday[$count]=$s
     count=$((count+1))
 fi 
done
echo ${friday[2]} #third fri