05-17-2007
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Unix Daemon
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Join Date: Aug 2001
Location: Washington DC Area
Posts: 8,718
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Quote:
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Originally Posted by dLloydm
There is one more thing I would like to verify. The course has the following question:
What do you think is the output of the following piece of code?
((x = 2#1101 & 2#110))
((y = ~x))
print - $y
The answer given is 11, as in decimal eleven or 2#1011.
From what I understand I think the answer should be -5 as in -2#101.
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You are correct:
$ ((x = 2#1101 & 2#110))
$ ((y = ~x))
$ print - $y
-5
$ |
