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Top Forums Shell Programming and Scripting Getting week number of the "Monday" Post 302095501 by sbasetty on Tuesday 7th of November 2006 07:20:17 PM
Old 11-07-2006
Thank Jean,


For calculating the previous month/year week the code is giving error.
when I run it displays week number as null for input value of "1 11"

I have replaced it with nawk now it displays as "0".

What will the /^[[:digit:][:space:]]*$/ statement will do
can you explain .
Can you please helpme with this.

With "nawk"

myWeek=$(cal "{wmonth}" "${wyear}" | \
nawk '
/^[[:digit:][:space:]]*$/ && NF>0 {
if (substr($0, 1, 2) != " ") wm += 1;
}
END { printf("%d\n", wm) }
')
echo "myWeek number is -> [${myWeek}]"


Thanks a lot Smilie

Last edited by sbasetty; 11-07-2006 at 09:20 PM..
 

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INTLCALENDAR.SETFIRSTDAYOFWEEK(3)					 1					 INTLCALENDAR.SETFIRSTDAYOFWEEK(3)

IntlCalendar::setFirstDayOfWeek - Set the day on which the week is deemed to start

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SYNOPSIS
public bool IntlCalendar::setFirstDayOfWeek (int $dayOfWeek) DESCRIPTION
Procedural style bool intlcal_set_first_day_of_week (IntlCalendar $cal, int $dayOfWeek) Defines the day of week deemed to start the week. This affects the behavior of fields that depend on the concept of week start and end such as IntlCalendar::FIELD_WEEK_OF_YEAR and IntlCalendar::FIELD_YEAR_WOY. PARAMETERS
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