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Full Discussion: Getting week number of the "Monday"
Top Forums Shell Programming and Scripting Getting week number of the "Monday" Post 302095455 by aigles on Tuesday 7th of November 2006 07:52:58 AM
Old 11-07-2006
Try and adapt the following script (based on cal command output) :
Code:
day=${1:-$(date +%e)}
month=${2:-$(date +%m)}
year=${3:-$(date +%Y)}

#
# Determine week in the month
#

wmonth=${month}
wyear=${year}

cal ${wmonth} ${wyear} | \
awk -v day="$day" '
        /^[[:digit:][:space:]]*$/ && NF>0 {
           if (substr($0, 1, 2) != "  ") wm += 1;
              for (i=1; i<=NF; i++) {
                if ($i+0 == day+0) {
                    print wm;
                    exit;
                 }
              }
           }
    ' | read week

#
# Determine week in previous month
#

if [ -z "${week}" ]
then

   # Previous month/year

   (( wmonth = month - 1 ))
   if (( wmonth == 0 ))
   then
      wmonth=12
      (( wyear -= 1))
   fi

   # Determine week

   cal ${wmonth} ${wyear} | \
   awk '
        /^[[:digit:][:space:]]*$/ && NF>0 {
           if (substr($0, 1, 2) != "  ") wm += 1;
        } 
        END { print wm }
    ' | read week
fi

#
# Display result
#

echo "Date = ${day}-${month}-${year}, Week.Month.Year = ${week}.${wmonth}.${wyear}"

Examples:
Code:
$ wm.ksh
Date =  7-11-2006, Week.Month.Year = 1.11.2006

$ wm.ksh 1 11
Date = 1-11-2006, Week.Month.Year = 5.10.2006


Jean-Pierre.
 

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LEARN ABOUT CENTOS

cal

CAL(1)								   User Commands							    CAL(1)

NAME

       cal - display a calendar

SYNOPSIS

       cal [options] [[[day] month] year]

DESCRIPTION

       cal displays a simple calendar.	If no arguments are specified, the current month is displayed.

OPTIONS

       -1, --one
	      Display single month output.  (This is the default.)

       -3, --three
	      Display prev/current/next month output.

       -s, --sunday
	      Display Sunday as the first day of the week.

       -m, --monday
	      Display Monday as the first day of the week.

       -j, --julian
	      Display Julian dates (days one-based, numbered from January 1).

       -y, --year
	      Display a calendar for the current year.

       -V, --version
	      Display version information and exit.

       -h, --help
	      Display help screen and exit.

PARAMETERS

       A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
       for 1989.

       Two parameters denote the month (1 - 12) and year.

       Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal.  If	no
       parameters are specified, the current month's calendar is displayed.

       A year starts on Jan 1. The first day of the week is determined by the locale.

       The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
       ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation,	so
       the calendar for that month is a bit unusual.

HISTORY

       A cal command appeared in Version 6 AT&T UNIX.

AVAILABILITY

       The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.

util-linux							     June 2011								    CAL(1)
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