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#1
11-01-2006
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du -h | sort ?
Hi all,
I want to sort a directory by file size, du -k |sort -nr is fine, but the output number is NOT friendly. So how to sort more friendly with du -h ? 
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#2
11-02-2006
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The problem with -h is that you end up with things like K, M and G for kB, MB, or GB (I think, I have no access to Linux right now to actually verify this). So you are better off using -k if you want to sort it.
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#3
11-02-2006
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I have an approach
du -k |sort -nr > sort_file.txt. The output file will be like this: 3783749 . 5294 ./dir3 4790 ./dir3/dir5/dir1 3088 ./dir8 ... can you help me on how to convert the number from sort_file.txt to MB, GB format, like this: 3.6 GB . 5.2 MB ./dir3 4.7 MB ./dir3/dir5/dir1 3 MB ./dir8 ... Thanks
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#4
11-02-2006
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You can use awk to format the size field :
Code:
du -k | sort -nr | awk '
BEGIN {
split("KB,MB,GB,TB", Units, ",");
}
{
u = 1;
while ($1 >= 1024) {
$1 = $1 / 1024;
u += 1
}
$1 = sprintf("%.1f %s", $1, Units[u]);
print $0;
}
' > sort_file.txt
Jean-Pierre
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#5
11-02-2006
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Thank Jean-Pierre,
your script with awk works, but the calculation is not correct. My actual data like this: 126M /openoffice/bin 31M /openoffice/old_versions but it report: 0.1 MB /openoffice/bin 0.0 MB /openoffice/old_versions Could you please correct it! Thank so much!
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