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Full Discussion: Remove content from file
Top Forums Shell Programming and Scripting Remove content from file Post 302087175 by jambesh on Wednesday 30th of August 2006 05:55:21 AM
Old 08-30-2006
what my approach is

today=`date '+%m-%d-Y'`
grep -v "$today" file_name >file_name

Last edited by jambesh; 08-31-2006 at 05:27 AM.. Reason: update
 

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FINFO_FILE(3)								 1							     FINFO_FILE(3)

finfo_file - Return information about a file

       Procedural style

SYNOPSIS
string finfo_file NULL NULL (resource $finfo, string $file_name, [int $options = FILEINFO_NONE], [resource $context]) DESCRIPTION
Object oriented style string finfo::file NULL NULL (string $file_name, [int $options = FILEINFO_NONE], [resource $context]) This function is used to get information about a file. PARAMETERS
o $finfo - Fileinfo resource returned by finfo_open(3). o $file_name - Name of a file to be checked. o $options - One or disjunction of more Fileinfo constants. o $context - For a description of contexts, refer to "Stream Functions". RETURN VALUES
Returns a textual description of the contents of the $file_name argument, or FALSE if an error occurred. EXAMPLES
Example #1 A finfo_file(3) example <?php $finfo = finfo_open(FILEINFO_MIME_TYPE); // return mime type ala mimetype extension foreach (glob("*") as $filename) { echo finfo_file($finfo, $filename) . " "; } finfo_close($finfo); ?> The above example will output something similar to: text/html image/gif application/vnd.ms-excel SEE ALSO
finfo_buffer(3). PHP Documentation Group FINFO_FILE(3)
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