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Top Forums UNIX for Dummies Questions & Answers using sed to append text to the end of each line Post 302081480 by GT Premi on Tuesday 25th of July 2006 03:33:49 PM
Old 07-25-2006
Not quite sure what you're saying, but assuming you have a datafile that contains:

1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
1 2 3 4 5

and you want it formatted as you've shown, you could do:
awk '{print $1, $2"\n"$3, $4, $5"\n\n"}' <datafile>

to get:
1 2
3 4 5

1 2
3 4 5
etc.

The above could also be accomplished with "awk '{printf}'".

I can't see the usefulness of adding tabs to the end of each line unless you plan to paste a file to this one, but you can do:
sed 's/$/[press TAB button here]/' datafile > newfile
 

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create_datafile_index(3alleg4)					  Allegro manual				    create_datafile_index(3alleg4)

NAME
create_datafile_index - Creates an index for a datafile. Allegro game programming library. SYNOPSIS
#include <allegro.h> DATAFILE_INDEX *create_datafile_index(const char *filename); DESCRIPTION
Creates an index for a datafile, to speed up loading single objects out of it. This is mostly useful for big datafiles, which you don't want to load as a whole. The index will store the offset of all objects inside the datafile, and then you can load it quickly with "load_datafile_object_indexed" later. Use destroy_datafile_index to free the memory used by it again. Note: If the datafile uses global compression, there is no performance gain from using an index, because seeking to the offset still requires to uncompress the whole datafile up to that offset. Example: DATAFILE_INDEX *index = create_datafile_index("huge.dat"); DATAFILE *object = load_datafile_object_indexed(index, 1234); ... unload_datafile_object(object); destroy_datafile_index(index); RETURN VALUE
A pointer value which you can pass to load_datafile_object_indexed. SEE ALSO
destroy_datafile_index(3alleg4), load_datafile_object_indexed(3alleg4) Allegro version 4.4.2 create_datafile_index(3alleg4)
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