03-27-2002
Thanks !
I always looked in the default id command and I did not look in the options.
This will work for me.
Sanjay
Quote:
Originally posted by killerserv
Have you try the id command ?
id [-gnruG] [--group] [--name] [--real] [--user] [--groups] [--help] [--version] [username]
By default, it prints the real user ID, real group ID, effective user ID if different from the real user ID, effective group ID if dif ferent from the real group ID, and supplemental group IDs. It prints each of these values preceded by a string identifying it and followed by the corresponding user or group name in parentheses. Post back if this doesnt help..
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id(1) General Commands Manual id(1)
Name
id - print user and group ID and names
Syntax
id [ -gnru ]
Description
The command writes a message on the standard output giving the user and group ID and the corresponding names of the invoking process. If
the effective and real IDs do not match, both are printed.
If multiple groups are supported by the underlying system, the supplementary group affiliations of the invoking process are also written.
When no options are specified, the standard format of output produced by is uid=%d(%s) gid=%d(%s), <real user id>, <user-name>, <real group
id>, <group-name>
Options
-g Outputs only the group ID. The default format is %d
. This may be modified by the -n option. The default group ID is the effective
group ID; this may be modified by the -r option.
-n Outputs the name in the format %s
instead of the numeric ID when the -u or -g options are used.
-r Outputs the real ID instead of the effective ID when the -u or -g options are used. There is no option to produce a list of supple-
mentary group IDs alone.
-u Outputs only the user ID. The default output format is %d0fP. This may be modified with the -n option. The default user ID is the
effective user ID; this may be modified by the -r option.
See Also
logname(1), getuid(2)
id(1)