Sponsored Content
Top Forums Shell Programming and Scripting subtracting a days from current date Post 101587 by rameshspal on Friday 10th of March 2006 12:10:48 AM
Old 03-10-2006
subtracting a days from current date

Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.

Ramesh
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

adding or subtracting days in the o/p of date

how can we add or subtract days from the output of date command in unix... like if i want to subtract a day from the result of date command like this.. v_date=`date +%Y%m%d` this wud give me 20080519 now i want to subtract one day from this.. so tht it wud give me 20080518.. how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies

2. Shell Programming and Scripting

How to find a date which is 7 days past when given current date

hii all. I have to get the date of the 7th day past from the current date. if i give the current date as sep 3 then i must get the date as 27th of august. can we get the values from the "cal" command. cal | awk '{print $2}' will this type of command work. actually my need is if today is... (17 Replies)
Discussion started by: ladtony
17 Replies

3. Shell Programming and Scripting

how to get what date was 28 days ago of the current system date IN UNIX

Hi, Anybody knows how to get what date was 28 days ago of the current system date through UNIX script. Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies

4. Shell Programming and Scripting

Date after 5 days from current date in YYYYMMDD format

Hello Experts, How do i get date after 5 days from current date in YYYYMMDD format? How do you compare date in YYYYMMDD format? Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies

5. Windows & DOS: Issues & Discussions

Adding or subtracting days from current date in batch script

Hi, I'm writing an batch file to create report In the batch file iam passing two arguments:startdate and finishdate Ex: startdate=07-sep-2009 finishdate=07-sep-2011 I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Discussion started by: anand1773
2 Replies

6. Shell Programming and Scripting

How to Get 60 days Old date from current date in KSH script

Hi i am writing a cron job. so for it i need the 60 days old date form current date in variable. Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27. i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
Discussion started by: Himanshu_soni
3 Replies

7. Shell Programming and Scripting

Number of days between the current date and user defined date

I am trying to find out the number of days between the current date and user defined date. I took reference from here for the date2jd() function. Modified the function according to my requirement. But its not working properly. Original code from here is working fine. #!/bin/sh... (1 Reply)
Discussion started by: hiten.r.chauhan
1 Replies

8. UNIX for Dummies Questions & Answers

Subtracting number of days from current date

Hi All, I am using KSH shell and need to subtract n number of days from the current date .. kindly suggest ! Thanks in advance!:) (20 Replies)
Discussion started by: dev.devil.1983
20 Replies

9. UNIX for Beginners Questions & Answers

Subscribers with Date 90 days older than current date

I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date. Below command is used for this purpose: cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
Discussion started by: dia
1 Replies

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
lchage(1)						      General Commands Manual							 lchage(1)

NAME
lchage - Display or change user password policy SYNOPSIS
lchage [OPTION]... user DESCRIPTION
Displays or allows changing password policy of user. OPTIONS
-d, --date=days Set the date of last password change to days after Jan 1 1970. Set days to -1 to disable password expiration (i.e. to ignore --mindays, and --maxdays and related settings). Set days to 0 to enforce password change on next login. (This also disables password expiration until the password is changed.) -E, --expire=days Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration. -i, --interactive Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration. -I, --inactive=days Disable the account after days after password expires (after the user is required to change the password). Set days to -1 to keep the account enabled indefinitely after password expiration. -l, --list Only list current user's policy and make no changes. -m, --mindays=days Require at least days days between password changes. Set days to 0 or -1 to disable this requirement. If this value is larger than the value set by --maxdays, the user cannot change the pasword. -M, --maxdays=days Require changing the password after days since last password change. Set days to -1 to disable password expiration. -W, --warndays=days Start warning the user days before password expires (before the user is required to change the password). Set days to 0 or -1 to disable the warning. EXIT STATUS
The exit status is 0 on success, nonzero on error. NOTES
Note that "account expiration" (set by --expire) is distinct from "password expiration" (set by --maxdays). Account expiration happens on a fixed date regardless of password changes. Password expiration is relative to the date of last password change. libuser Nov 8 2012 lchage(1)
All times are GMT -4. The time now is 08:27 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy