Sponsored Content
Top Forums Shell Programming and Scripting subtracting a days from current date Post 101587 by rameshspal on Friday 10th of March 2006 12:10:48 AM
Old 03-10-2006
subtracting a days from current date

Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.

Ramesh
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

adding or subtracting days in the o/p of date

how can we add or subtract days from the output of date command in unix... like if i want to subtract a day from the result of date command like this.. v_date=`date +%Y%m%d` this wud give me 20080519 now i want to subtract one day from this.. so tht it wud give me 20080518.. how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies

2. Shell Programming and Scripting

How to find a date which is 7 days past when given current date

hii all. I have to get the date of the 7th day past from the current date. if i give the current date as sep 3 then i must get the date as 27th of august. can we get the values from the "cal" command. cal | awk '{print $2}' will this type of command work. actually my need is if today is... (17 Replies)
Discussion started by: ladtony
17 Replies

3. Shell Programming and Scripting

how to get what date was 28 days ago of the current system date IN UNIX

Hi, Anybody knows how to get what date was 28 days ago of the current system date through UNIX script. Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies

4. Shell Programming and Scripting

Date after 5 days from current date in YYYYMMDD format

Hello Experts, How do i get date after 5 days from current date in YYYYMMDD format? How do you compare date in YYYYMMDD format? Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies

5. Windows & DOS: Issues & Discussions

Adding or subtracting days from current date in batch script

Hi, I'm writing an batch file to create report In the batch file iam passing two arguments:startdate and finishdate Ex: startdate=07-sep-2009 finishdate=07-sep-2011 I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Discussion started by: anand1773
2 Replies

6. Shell Programming and Scripting

How to Get 60 days Old date from current date in KSH script

Hi i am writing a cron job. so for it i need the 60 days old date form current date in variable. Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27. i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
Discussion started by: Himanshu_soni
3 Replies

7. Shell Programming and Scripting

Number of days between the current date and user defined date

I am trying to find out the number of days between the current date and user defined date. I took reference from here for the date2jd() function. Modified the function according to my requirement. But its not working properly. Original code from here is working fine. #!/bin/sh... (1 Reply)
Discussion started by: hiten.r.chauhan
1 Replies

8. UNIX for Dummies Questions & Answers

Subtracting number of days from current date

Hi All, I am using KSH shell and need to subtract n number of days from the current date .. kindly suggest ! Thanks in advance!:) (20 Replies)
Discussion started by: dev.devil.1983
20 Replies

9. UNIX for Beginners Questions & Answers

Subscribers with Date 90 days older than current date

I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date. Below command is used for this purpose: cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
Discussion started by: dia
1 Replies

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
CAL(1)							    BSD General Commands Manual 						    CAL(1)

NAME
cal, ncal -- displays a calendar and the date of Easter SYNOPSIS
cal [-3hjy] [-A number] [-B number] [[month] year] cal [-3hj] [-A number] [-B number] -m month [year] ncal [-3hjJpwy] [-A number] [-B number] [-s country_code] [[month] year] ncal [-3hJeo] [-A number] [-B number] [year] ncal [-CN] [-H yyyy-mm-dd] [-d yyyy-mm] DESCRIPTION
The cal utility displays a simple calendar in traditional format and ncal offers an alternative layout, more options and the date of Easter. The new format is a little cramped but it makes a year fit on a 25x80 terminal. If arguments are not specified, the current month is dis- played. The options are as follows: -h Turns off highlighting of today. -J Display Julian Calendar, if combined with the -e option, display date of Easter according to the Julian Calendar. -e Display date of Easter (for western churches). -j Display Julian days (days one-based, numbered from January 1). -m month Display the specified month. If month is specified as a decimal number, it may be followed by the letter 'f' or 'p' to indicate the following or preceding month of that number, respectively. -o Display date of Orthodox Easter (Greek and Russian Orthodox Churches). -p Print the country codes and switching days from Julian to Gregorian Calendar as they are assumed by ncal. The country code as deter- mined from the local environment is marked with an asterisk. -s country_code Assume the switch from Julian to Gregorian Calendar at the date associated with the country_code. If not specified, ncal tries to guess the switch date from the local environment or falls back to September 2, 1752. This was when Great Britain and her colonies switched to the Gregorian Calendar. -w Print the number of the week below each week column. -y Display a calendar for the specified year. -3 Display the previous, current and next month surrounding today. -A number Display the number of months after the current month. -B number Display the number of months before the current month. -C Switch to cal mode. -N Switch to ncal mode. -d yyyy-mm Use yyyy-mm as the current date (for debugging of date selection). -H yyyy-mm-dd Use yyyy-mm-dd as the current date (for debugging of highlighting). A single parameter specifies the year (1-9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calendar for 1989. Two parameters denote the month and year; the month is either a number between 1 and 12, or a full or abbreviated name as speci- fied by the current locale. Month and year default to those of the current system clock and time zone (so ``cal -m 8'' will display a calen- dar for the month of August in the current year). Not all options can be used together. For example ``-3 -A 2 -B 3 -y -m 7'' would mean: show me the three months around the seventh month, three before that, two after that and the whole year. ncal will warn about these combinations. A year starts on January 1. Highlighting of dates is disabled if stdout is not a tty. SEE ALSO
calendar(3), strftime(3) HISTORY
A cal command appeared in Version 5 AT&T UNIX. The ncal command appeared in FreeBSD 2.2.6. AUTHORS
The ncal command and manual were written by Wolfgang Helbig <helbig@FreeBSD.org>. BUGS
The assignment of Julian-Gregorian switching dates to country codes is historically naive for many countries. Not all options are compatible and using them in different orders will give varying results. BSD
March 14, 2009 BSD
All times are GMT -4. The time now is 05:14 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy